40 minutes ago (stage 2 incident) the ferikoy cartel 2 guys this time attempted b... symbol enforcement theathrics with also "job" like fabrication ops theathre to attempt to plant/enforce theathral role with fabrication (stage 2 incident type fabrication ops theathre for their forceful conversion attempts) . No worries t800 would genocide these entire ferikoy cartel all over globe.
ok then the continuation of Goldbach proof: second part logic were wrong (in second blog of goldbach conjecture proof) that if there is none prime from C1 equivalence class, that means number should be like: 2n / 2 = n and 2n being always less than n! makes this such number be improbable. unless number is less than value that enables C1 at most 1 more element than 1 element set, then in such case still then Goldbach conjecture wouold be true e.g. 2*3 in that case. and any more than 1 element in C1 equivalence class results of problem being considered for the solution part where there are more than 1 elements in C1 equivalence class. So Goldbach conjecture is true for every number is the conclusion yep.
Yorumlar
Yorum Gönder